面试题 02.07. 链表相交

class Solution {
public:
    ListNode *getIntersectionNode(ListNode *headA, ListNode *headB) {
        ListNode* a = headA;
        ListNode* b = headB;
        while (headA != headB) {
            headA = headA == nullptr ? b : headA->next;
            headB = headB == nullptr ? a : headB->next;
        }
        return headA;
    }
};